800b^-4+40=90

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Solution for 800b^-4+40=90 equation: 



800b^-4+40=90

We move all terms to the left:

800b^-4+40-(90)=0

We add all the numbers together, and all the variables

800b-54=0

We move all terms containing b to the left, all other terms to the right

800b=54

b=54/800

b=27/400

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